1.CAPACITY IN M.T :
(Total Area-alley ways)*height in no of layers of the bags/Area occupied by each bag*weight of one bag /1000
= (100-20) 5m*100/2m*1000
= 80*5*100/1000
= 40/2
= 20 M.T.
NOTE:Provision for all ways is 20% of the total area.
(Total Area-alley ways)*height in no of layers of the bags/Area occupied by each bag*weight of one bag /1000
= (100-20) 5m*100/2m*1000
= 80*5*100/1000
= 40/2
= 20 M.T.
NOTE:Provision for all ways is 20% of the total area.
2.CAPACITY IN NO. OF BAGS :(100 Kg)
(Total Area-alley ways)*no.of layers of bags/area occupied by one bag/area occupied by one bag=(100-20)*5m/2m
=80*5/2
=400/2
=200 bags.
Area of the stack:(Sq.M.) = 2H(L+B)+(L*B)
= 2*3.6(5.4+3)+(5.4*3)
= 2*3.6(8.4)+16.2
=60.48+16.20
=76.68 sq.m
where L=Length in meters ; B=Breadth in meters ;H=Height in meters.
=60.48+16.20
=76.68 sq.m
where L=Length in meters ; B=Breadth in meters ;H=Height in meters.
No comments:
Post a Comment